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Comment Cell Phone.Comment Cell Phone InformationThe Ratapult Objective: My objective in this project was to produce a rat-trap powered catapult. It has a base of 30 cm by 30 cm, and has a theme of cows trying to escape the farm. The reason they want to escape is because they are being killed and turned into steaks, against there will. That is why I developed this ratapult, to save the cows. The cows also wanted me to ask you to eat more chicken. Hypothesis and Drawing: I hypothesize that if I build the ratapult to a 25-degree angle, and release the hacky sack at a height of .55m then there will be enough velocity to project the hacky sack exactly four meters. The ratapult will release the hacky sack with an initial velocity of 5.8 m/s, and as a result the hacky sack will travel 4.0 meters in .75 seconds. Procedure: The first step I took was to paint all of the wood white. After that I put wallpaper on the board that I am going to nail the rat trap to. I then attached the measuring cup to the rat trap by drilling a hole in the middle of the measuring cup and then using string to attach the cup at both the drilled hole, and the hole at the bottom. Then I nailed the rat trap into the board with wallpaper. That board was then nailed into the base. Then I attached the “steps” to the milk crate. The steps will hold the base of the ratapult at a 25-degree angle. I attached the “steps” by drilling holes in the bottom of them and then tying them to the milk crate. Then I nailed the board with wallpaper into the back end of the base. The base was then nailed into the “steps”, and glued grass decorations and cardboard cows to the base. The ratapult was completed. Data & Observations: I found the initial velocity, or Vi, by finding the horizontal velocity, or Vx, and then using the equation Vx = Vi * cos(angle). The angle was 25 degrees, so I input that into the equation also. That made the equation look like 5.3 m/s = Vi * cos(25) I divided both sides by sin(25), then that gave me an initial velocity of 5.8 m/s. Then I decided to find the Vertical height of the hacky sack, so I used the equation Vy = Vi * sin(angle). Vy stands for initial vertical velocity. I used the initial velocity that I had already found, then input 25 for angle, and that gave me an equation that looked like Vy = (5.8m/s) * sin(25) That gave me an initial vertical velocity of 2.47 m/s. I then used the equation y = Vyt + ˝gt . y stands for vertical height, while t stands for time, and g stands for gravity. That makes the equation look like y = (2.47m/s)(.375s) + ˝(-9.80)(.375) That gave me a vertical height of .237m. I then added that to the initial height that the hacky sack was launched from, which was .55m. That gave me a total height of .787m. That means that my hacky sack had an initial velocity of 5.8m/s, and went a total of .787m high. Conclusion: I have accomplished my goal and built a catapult using a rat trap. The ratapult has done everything that it has been required to do, and more. It will never break down, or be destroyed because it has launched too many hacky sacks. It is as sturdy as a catapult can be, and has plenty of power. It is the ideal catapult that is made out of a rat trap, and in my opinion, the best. |